Question by Alexis: chemistry reaction problem?? about mass? please help! thanks!?
An experiment that led to the formation of the new field of organic chemistry involved the synthesis of urea, CN2H4O, by the controlled reaction of ammonia and carbon dioxide.
2 NH3(g) + CO2(g) CN2H4O(s) + H2O(l)
What is the mass of urea when ammonia is reacted with 100. g of carbon dioxide?
Answer by jreut
Use dimensional analysis and stoichiometry:
100 g CO2 x 1 mole CO2 / 44 g CO2 x 1 mol urea / 1 mole CO2 x 60 g urea / 1 mole urea =
100/44*60= 136. grams of urea produced.
The first term, 100 g CO2, is your starting amount.
The second fraction, 1 mol CO2 / 44 g CO2, is a conversion factor that equals 1, since there are 44 g CO2 in a mole of CO2.
The third fraction is the stoichiometric ratio in the chemical equation: for every one mole of CO2 consumed, 1 mol of urea is formed.
The fourth fraction is the conversion factor back to grams.
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